0=12x^2-4x+36

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Solution for 0=12x^2-4x+36 equation: 



0=12x^2-4x+36

We move all terms to the left:

0-(12x^2-4x+36)=0

We add all the numbers together, and all the variables

-(12x^2-4x+36)=0

We get rid of parentheses

-12x^2+4x-36=0

a = -12; b = 4; c = -36;
Δ = b2-4ac
Δ = 42-4·(-12)·(-36)
Δ = -1712
Delta is less than zero, so there is no solution for the equation

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